In the given reaction,
$Ph-C \equiv C-CH_3 \xrightarrow{H^{+}/Hg^{2+}} A$
the product $A$ is

  • A
    $Ph-CH=C(OH)-CH_3$
  • B
    $HO-C(Ph)=CH-CH_3$
  • C
    $Ph-CO-CH_2CH_3$
  • D
    $Ph-CH_2-CO-CH_3$

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